Question

mole of O2 required to produce 160 grams of so3 from a SO2 is​

Answer 1

2so2+ o2---2so3(balanced)

1 mole o2--- 160g of so3.

so answer is 1 mole of o2.

Answer 2

Answer : The moles of $O_2$ required will be, 1 mole

Explanation : Given,

Mass of $SO_3$ = 160 g

Molar mass of $SO_3$ = 80 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $SO_3$.

$\text{Moles of }SO_3=\frac{\text{Mass of }SO_3}{\text{Molar mass of }SO_3}=\frac{160g}{80g/mole}=2moles$

Now we have to calculate the moles of $O_2$.

The balanced chemical reaction is,

$2SO_2+O_2\rightarrow 2SO_3$

From the balanced reaction we conclude that

As, 2 moles of $SO_3$ obtained from 1 mole of $O_2$

So, given 2 moles of $SO_3$ also obtained from 1 mole of $O_2$

Therefore, the moles of $O_2$ required will be, 1 mole