Mona is 20% younger than neetu. how much percent neetu is older than mona.
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Let the age of neetu be x years.
age of mona= x- 20%of x= x- 20x/100
age of mona= x-x/5= (5x-x)/5= 4x/5
age difference between neetu & mona=
x- 4x/5= (5x-4x)/5= x/5
Neetu is older than mona = (age difference/age of mona)×100
Neetu is older than mona=( (x/5)/(4x/5)) ×100
Neetu is older than mona= (x/5) × (5/4x) ×100
= 100/4= 25%
Hence Neetu is older than Mona by 25%
age of mona= x- 20%of x= x- 20x/100
age of mona= x-x/5= (5x-x)/5= 4x/5
age difference between neetu & mona=
x- 4x/5= (5x-4x)/5= x/5
Neetu is older than mona = (age difference/age of mona)×100
Neetu is older than mona=( (x/5)/(4x/5)) ×100
Neetu is older than mona= (x/5) × (5/4x) ×100
= 100/4= 25%
Hence Neetu is older than Mona by 25%
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