Question

Monochromatic light of frequency 6.0x 1014 Hz is produced by a laser. What is the energy of a photon in the light beam?

Answer 1

Energy , E = hv ( consider v to be the frequency of light)

therefore
E = 6.625 × 10^-34 × 6.0 × 1014 = 4.03 × 10^-30 Joules

Answer 2

Answer: The energy of a photon in the light beam is $E = 39.6\times10^{-20}\ J$

Explanation:

Given that,

Frequency $f = 6.0\times10^{14}Hz$

We know that,

The energy of photon is the product of the frequency of the light and plank constant.

The energy of photon is

$E = hf$

$E = 6.6\times10^{-34}\ J-s\times 6.0\times10^{14}\ Hz$

$E = 39.6\times10^{-20}\ J$

Hence, The energy of a photon in the light beam is $E = 39.6\times10^{-20}\ J$