Morning breakfast gives 5000 cal to a 60 kg person. The efficiency of person is 30%. the height upto which the person can climb up by using energy obtained from breakfast is? Ans 10.5 m How?
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Answered by
116
Energy of man= E = 5000 cal or 20920 J
mass of the man = m = 60 kg
height climbed by the man = h
so the energy utilized by the man will be = mgh
since the efficiency of the man is 30% and he used all his energy
so,
mgh = 60 x 9.8 x h
h = 10.6 m
mass of the man = m = 60 kg
height climbed by the man = h
so the energy utilized by the man will be = mgh
since the efficiency of the man is 30% and he used all his energy
so,
mgh = 60 x 9.8 x h
h = 10.6 m
Answered by
77
first of all you will calculate the energy and than you will equate it with mgh. And than you will get your answer....
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