Question

Motion of a particle is given by equation S=(3t3+7t2+14t+8)m The value of acceleration of the particle at t = 1 sec. is :

Answer 1

d= 3t³+7t²+5t+8. v=dx/dt. =9t^2+14t+5. a =dx^2/dt^2. =18t+14. a=18t+14. t=1. a= 32 m/s^2. option c is the right answer ...