Question

motorcyclist drives from a to b with a uniform speed of 30 km/hr and returns back with a speed of 20 km/hr find its average speed. what will be the acceleration

Answer 1

$\bold{Heya....!!!}$

Average Speed :-»

Let the distance be X and according to the question he returns back also so distance covered by him will be 2X

Average speed (v) = $\bold{v = X/T}$


We have to take out total Time ( T )

→ Total time ( T ) = (X/30 + X/20)

Average speed =  (2X ) / (X/30 + X/20)

while solving the above , distance X will be cancelled .

Average Speed :-»

$\huge\boxed{24 km/hr}$

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Hope It Helps You. ^_^

Answer 2

You can do like this first convert both the speed in m/s
Then as know average speed =total distance covered/ total time taken

Then you will get your ans

And for finding acceleration
A=v-u/t

This will give you acceleration

I can also give solution but I want you do yourself by my given step

I think it will help you to solve out your problem