The sum of square of two numbers is 68 and square of the difference of them is 36. Then multiplication
value of the two is ??
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Let x and y are two numbers.
x^2+y^2=68………………….(1)
(x-y)^2=36……………………….(2)
x^2+y^2–2x.y=36 , put x^2+ y^2=68 fromeq.(1)
68–2x.y=36
-2x.y=36–68
-2x.y= -32
x.y=32/2=16 , Answer
x^2+y^2=68………………….(1)
(x-y)^2=36……………………….(2)
x^2+y^2–2x.y=36 , put x^2+ y^2=68 fromeq.(1)
68–2x.y=36
-2x.y=36–68
-2x.y= -32
x.y=32/2=16 , Answer
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Answered by
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Let the numbers be X and Y.
A / q ,
X ^ 2 + Y ^ 2 = 68
X ^ 2 - Y ^ 2 = 36
adding these --
2X ^ 2 = 104
X ^ 2 = 104 / 2 = 52
X ^ 2 = 52
X = 7.2
52 - Y ^ 2 = 36
Y ^ 2 = 52 - 36
Y ^ 2 = 16
Y = 4
X * Y. = 7.2 * 4 = 28.8
A / q ,
X ^ 2 + Y ^ 2 = 68
X ^ 2 - Y ^ 2 = 36
adding these --
2X ^ 2 = 104
X ^ 2 = 104 / 2 = 52
X ^ 2 = 52
X = 7.2
52 - Y ^ 2 = 36
Y ^ 2 = 52 - 36
Y ^ 2 = 16
Y = 4
X * Y. = 7.2 * 4 = 28.8
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