Question

mr abrar invested two sums of money on simple intrest. the first was 22000 invested at 8% per annum and the second 19600 at 10 % per annum. the two sums were allowed to grow till both amounted to the same figure.in how many years did this happen and what was the finam amount​

Answer 1

Answer:

sorry but I don't know the answer of this question

Explanation:

sorry but I don't know the answer of this question

Answer 2

Answer:

t= 12 years            Final Sum = S₁+S₂ = 86240

Kinda late to help you but i hope it might help others

Explanation:

Lets

P₁= Principal Amount = 22000/=                    P₂= Principal Amount = 19600/=

r₁= Rate = 8%= 0.08                                         r₂= Rate = 10% = 0.10

                                                    t= time

A/C To Question:                            

S= Sum of money = S₁=S₂

Solution

S=P₁(1+r₁t)                                      S=P₂(1+r₂t)

S=22000(1+0.08t)                        S=19600(1+0.10t)

Now

22000 (1+0.08t) = 19600 (1-0.10t)

22000-19600 = 1960t-1760t

....

t= 12 years

put 't' in any of the above equation

S=22000(1+0.08t)

S=22000(1+0.08x12)

S=43120/=

Now

Final Sum of Amount = S₁+S₂= 43120+43120

Final Sum = 86240