mr abrar invested two sums of money on simple intrest. the first was 22000 invested at 8% per annum and the second 19600 at 10 % per annum. the two sums were allowed to grow till both amounted to the same figure.in how many years did this happen and what was the finam amount
Answers
Answer:
sorry but I don't know the answer of this question
Explanation:
sorry but I don't know the answer of this question
Answer:
t= 12 years Final Sum = S₁+S₂ = 86240
Kinda late to help you but i hope it might help others
Explanation:
Lets
P₁= Principal Amount = 22000/= P₂= Principal Amount = 19600/=
r₁= Rate = 8%= 0.08 r₂= Rate = 10% = 0.10
t= time
A/C To Question:
S= Sum of money = S₁=S₂
Solution
S=P₁(1+r₁t) S=P₂(1+r₂t)
S=22000(1+0.08t) S=19600(1+0.10t)
Now
22000 (1+0.08t) = 19600 (1-0.10t)
22000-19600 = 1960t-1760t
....
t= 12 years
put 't' in any of the above equation
S=22000(1+0.08t)
S=22000(1+0.08x12)
S=43120/=
Now
Final Sum of Amount = S₁+S₂= 43120+43120
Final Sum = 86240