Question

Mr kasam runs a small business of making earthen pots. he makes certain number of pots on daily basis. production cost of each is rs 40 more than 10 times total number of pots, he makes in one day. if production cost of all pots per day is rs 600,find production cost of one pot and number of pots he makes per day

Answer 1

Here is the answer

Let Kasam makes 'x' eathen pots per day .
Then the cost of each earthen pots is Rs.(10x + 40 )

From the given condition,

x(10x + 40) = 600

Therefore,

10x^2 +40x - 600 = 0

Dividing by 10 ,

x^2 + 4x - 60 = 0

x^2 + 10x - 6x - 60 = 0

x(x + 10) - 6(x + 10) = 0

(x - 6)(x + 10) = 0

x = -10 or x = 6

But the number of earthen pots cannot be negative.

So, x = -10 is not acceptable.

So,
x = 6

The cost of each earthen pots
= 10x + 40

= 10(6) + 40

= 60 + 40

= 100

Final answer

He makes 6 earthen pots per day and cost of each earthen pots is Rs 100

Answer 2

$\textbf{\huge{ANSWER:}}$

Let the number of pots Mr. Kasam makes be = x

Now, we're given that:

Mr. Kasam's production costs Rs.40 more than 10 times the total number of pots.
Equation:
10x + 40

Therefore, $\textbf{ATQ:}$

=》 x(10x + 40) = 600

=》 10x^2 + 40x = 600

=》 10x^2 + 40x - 600 = 0

To simplify the calculation, we can divide the equation by 10:

=》 x^2 + 4x - 60 = 0

=》 x^2 + 10x - 6x - 60 = 0

=》 x ( x + 10 ) - 6 ( x + 10 ) = 0

=》 ( x - 6 ) ( x + 10 ) = 0

=》 x - 6 = 0

=》 x = 6

Put the value of x in the equation, we first formed.

10(6) + 40

=》 60 + 40

=》 100

$\textbf{\huge{100 is the answer.}}$