Math, asked by aaru2010, 1 year ago

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

Answers

Answered by kunal0912
12

Let the, sum of scheme A and B be x and y respectively.

so, x + y = 13900 -----------------------------------------(1)

We are also given,

x*14*2/100 + y*11*2/100 = 3508

= 14x + 11y = 175400 ------------------------------------(2)

Solving (1) and (2) we get,

x =  Rs. 7500       and y = Rs. 6400

Hence, amount invested in scheme B was Rs. 6400

Answered by GauravSaxena01
10


solution:-

Let the total invested with in theme A be Rs. x and that in theme B be Rs. (13900 - x).
Then,
=> X×14×2 /100

=>13900-X × 11×2 /100

==> 3508

=>28X-22X = 350800- ( 13900x 22)

=> 6X = 45000
=> X= 7500

So, total invested with in theme 

B = Rs. (13900 - 7500) = Rs. 6400.

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@GauravSaxena01

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