Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
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Answered by
12
Let the, sum of scheme A and B be x and y respectively.
so, x + y = 13900 -----------------------------------------(1)
We are also given,
x*14*2/100 + y*11*2/100 = 3508
= 14x + 11y = 175400 ------------------------------------(2)
Solving (1) and (2) we get,
x = Rs. 7500 and y = Rs. 6400
Hence, amount invested in scheme B was Rs. 6400
Answered by
10
solution:-
Let the total invested with in theme A be Rs. x and that in theme B be Rs. (13900 - x).
Then,
=> X×14×2 /100
=>13900-X × 11×2 /100
==> 3508
=>28X-22X = 350800- ( 13900x 22)
=> 6X = 45000
=> X= 7500
So, total invested with in theme
B = Rs. (13900 - 7500) = Rs. 6400.
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@GauravSaxena01
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