Question

Mr. tripathi goes to office at the rate of 12.5 km/ hr and reaches 3 minutes late .however if he travels at 15 km / hr , he reaches 5 minutes early. what is the distance of mr. tripathi 's office from his residence ​

Answer 1

Step-by-step explanation:

plz mark me as brainliest

Answer 2

Step-by-step explanation:

Solution : Let the required distance = 1 km

Time taken to cover 1 km at 12.5 km/hr

=

$\frac{1}{12.5} \: hour \: = \: \frac{10}{125} \: hour \: = \: \frac{2}{25} hour \\ = \frac{2}{25} \times 60 \: minutes \: = \frac{2}{5} \: minutes \: = \: 4.8 \: minutes \:$

Time taken to cover 1 km at 15 km/hr

$= \frac{1}{15} \: hour \: = \: \frac{1}{15} \times 60 \: minutes \: = 4 \: minutes$

Different in time taken = (4.8 - 4) minutes = .8 minutes

But actual different in time = (3 + 5) minutes = 8 minutes

Now, more is the difference in the time taken at two speeds, more is the distance.

So, it is a case of direct variation

=> .8 : 8 : : 1 : x

=> .8 × x = 8 × 1

$x \: = \frac{8 \times 1}{8} = 10$

So,the required distance = 10 km.