Mrs. Alvarez asked her class how many hours of TV they watched per day (to the nearest half hour). The results are shown below. Hours of TV Fraction of class 000 to 111 \dfrac{1}{6} 6 1 start fraction, 1, divided by, 6, end fraction 1 \large\frac{1}{2}1 2 1 1, start fraction, 1, divided by, 2, end fraction to 222 \dfrac{5}{12} 12 5 start fraction, 5, divided by, 12, end fraction 2 \large\frac{1}{2}2 2 1 2, start fraction, 1, divided by, 2, end fraction to 333 \dfrac{1}{4} 4 1 start fraction, 1, divided by, 4, end fraction More than 333 \dfrac{1}{6} 6 1 start fraction, 1, divided by, 6, end fraction What fraction of the students watch between 000 and 222 hours of TV a day?
Answers
Answer:
Answer:
7/12
Step-by-step explanation:
The problem is asking us to find what fraction of students watch between 0 and 2 hours of TV a day:
The information we have is:
0 - 1 hours = 1/6
1 1/2 - 2 hours = 5/12
We only need this information because it is asking us for 0 to 2 hours.
Now we have to add the fraction of students that watch TV 0-1 hours and the fraction of students watch TV 1 1/2 - 2 hours:
1/6 + 5/12
To be able to solve this we have to have the same denominator and to do it we have to multiply the first fraction by 2:
(1/6) *2 = 2/12
Now we can add:
2/12 + 5/12 = 7/12
We add the numerators and the denominator stays the same.
Answer:
Step-by-step explanation:
7/12
Step-by-step explanation:
The problem is asking us to find what fraction of students watch between 0 and 2 hours of TV a day:
The information we have is:
0 - 1 hours = 1/6
1 1/2 - 2 hours = 5/12
We only need this information because it is asking us for 0 to 2 hours.
Now we have to add the fraction of students that watch TV 0-1 hours and the fraction of students watch TV 1 1/2 - 2 hours:
1/6 + 5/12
To be able to solve this we have to have the same denominator, and to do it we have to multiply the first fraction by 2:
(1/6) *2 = 2/12
Now we can add:
2/12 + 5/12 = 7/12
We add the numerators and the denominator stays the same.