Question

mrs joseph is27 years older than her daughter bindu after 8years she will be twice as old as bindu find their present age

Answer 1

Assume
Mrs Joseph age is x years,
Bindu age is y years
Equation 1=
(x)=(y)+27
x-y=27.......1
Equation 2=
(x+8)=2(y+8)
x+8=2y+16
x-2y=16-8
x-2y=8......2
{x+8 =after eight years}

Answer 2

Let the age of Bindu be x years.

Then the age of Mrs.Joseph will be x + 27 years.

After 8 years : 

The age of Bindu will be x + 8 years.

The age of Mrs.Joseph will be x + 8 + 27 = x + 35 years.


Given that Mrs. Joseph will be twice as old as Bindu.

x + 35 = 2(x + 8)

x + 35 = 2x + 16

x = 19.

then the age of Mrs.Joseph will be x + 27 = 19 + 27 = 46 years.


The age of Bindu = 19 years.

The age of Mrs.Joseph = 46 years.


Hope this helps!