Question

Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten, and the rest were either ripe or unripe. There were 18 more ripe oranges than unripe oranges. Find the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges. PLS HURRY

Answer 1

Answer:42

Step-by-step explanation:

Answer 2

$\bold{\underline{\underline{Answer:}}}$

Ratio = 39:24:21

$\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}$

Given :

• Mrs. Rifkin had 84 oranges
• 24 of her oranges were rotten
• There were 18 more ripe oranges than unripe oranges

To find :

• the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges

Solution :

Let the number of riped oranges be x.

Let the number of unriped oranges be y.

Number of rotten oranges = 24 [Given]

$\bold{\underline{\underline{As\:per\:the\:question}}}$

• There were 18 more ripe oranges than unripe oranges

Constituting it mathematically,

$\implies$ $\bold{x\:=\:y\:+\:18}$

$\implies$ $\bold{x\:-\:y=18}$ ----> (1)

Total Number of orange = 84

Which includes, riped oranges, unriped oranges and rotten oranges.

•°• $\bold{x+y+24\:=84}$

$\bold{x+y=84\:-\:24}$

$\bold{x+y=\:60}$ ----> (2)

Solve equations 1 and 2 simultaneously by elimination method.

Add equation 2 to equation 1,

x + y = 60

x - y = 18

---------------

2x = 78

$\bold{x\:=\frac{78}{2}}$

$\bold{x\:=\:39}$

Substitute x = 39 in equation 1,

x - y = 18 ----> (1)

39 - y = 18

39 - 18 = y

21 = y

•°• y = 21

•°• Number of riped oranges, x = 39

Number of unriped oranges, y = 21

Number of rotten oranges = 24

Ratio = x : 24 : y

•°•Required ratio = 39 : 24 : 21