Question

multiply (2√-3+3√-2)by(4√-3-5√-2)

Answer 1

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Answer 2

Answer:

It is multiplication of Complex Number

(2√-3+3√-2) by (4√-3-5√-2)

= (2√3i+3√2i) (4√3i-5√2i)

= i²(2√3+3√2) (4√3-5√2)

= -1(24-10√6+12√6-30)

= -1(-6+2√6)

= 6-2√6

= 6-2√-6i [ because i²= -1]

Step-by-step explanation:

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