Question

multiply:-
(y²+2y+3) × (y²+2y-3)​

Answer 1

Answer:

$(( {y }^{2} + 2y) + 3 ) \times (({y }^{2} + 2y) - 3) \\ = {( {y}^{2} + 2y )}^{2} - {3}^{2} \\ = {y}^{4} + 4 {y}^{2} + 4 {y}^{3} - 9 \\ = {y}^{4} + 4 {y}^{3} + 4 {y}^{2} - 9$

Answer 2

Answer:

[{(y^2) +2y}+3] ×[{(y^2)+2y}-3]

we know (a+b)(a-b) =( a^2)-(b^2)

here , a=y^2+2y , b=3

so, (y^2+2y)^2 - 3^2

next you solve....