(mx-ma)(mx-mb)-m(a-b)-1 = 0
Find the value of X
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Answer:
a + 1/m & b- 1/m
Step-by-step explanation:
(mx-ma)(mx-mb)-m(a-b)-1 = 0
Find the value of x
(mx-ma)(mx-mb)-m(a-b)-1 = 0
=> m(x-a)m(x-b) - m(a-b) - 1= 0
=> m²(x² - x(a + b) + ab) - m(a-b) - 1= 0
=> m²x² - m²(a +b)x + m²ab - m(a-b) - 1= 0
x = {- (-m²)(a+b) ± ( √ ((-m²)(a+b))² - 4m²( m²ab - m(a-b) - 1) ) } / 2m²
=> x = { m²(a+b) ± ( √ ((m²)(a-b))² + 4m² (m(a-b)) + 4m²) ) } / 2m²
=> x = { m²(a+b) ± ( √( (m²(a-b) + 2m)² ) } / 2m²
=> x = { m²(a+b) ± ( (m²(a-b) + 2m) } / 2m²
x = { m²(a+b) + ( (m²(a-b) + 2m) } / 2m² = a + 1/m
x = { m²(a+b) - ( (m²(a-b) + 2m) } / 2m² = b - 1/m
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