My age is 5 more than square of age of my son. After 5 years my age will five years more than trice age if my son then my present age is
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60
Answers
GIVEN :
- My age is 5 more than square of age of my son.
- After 5 years my age will five years more than trice age of my son.
TO FIND :
- My present age.
SOLUTION :
Let my son's present age be x years and my present age be y years.
✪ CASE 1✪
My age is 5 more than square of my son's age.
My age = (x²+5) years
According to the question,
y = x²+5............(i)
✪ CASE 2 ✪
After 5 years,
My age = (y+5) years
My son's age = (x+5) years
After 5 years my age will five years more than trice age of my son.
According to the question,
y+5 = 3(x+5)+5
† Putting y=x²+5 from eq(i) †
→ x²+5 +5= 3x+15+5
→ x² - 3x = 10
→x² -3x -10= 0
→ x ² -(5-2)x -10=0
→ x ² -5x +2x-10=0
→ x(x-5)+2(x-5) = 0
→ (x-5) (x+2) = 0
Either ,
x - 5 = 0
→ x = 5
Or,
x + 2 = 0
→ x = -2
Son's present age = 5 years.
My present age = 5² +5 = 30 years.
Therefore , my present age is 30 years.
- My age is 5 more than square of age of my son.
- After 5 years my age will five years more than trice age if my son.
- My present age.
- Let my son's present age be x years and my present age y years.
- my age is 5 more than square of my son's age.
my age = (x² + 5).
y + x² + 5_______(1)
my age = (y + 5) years.
my son's age = (x + 5) years.
y + 5 = 3(x + 5) + 5
putting y = x² + 5 Eq.____(1)
x² + 5 + 5 = 3x + 15 + 5
x² - 3x = 10
x² - 3x - 10 = 0
x²- (5 - 2)x - 10 = 0
x² - 5x + 2x - 10 = 0
x(x - 5) + 2(x - 5) = 0
(x - 5)(x + 2)
x + 5 = 0
x = 5
x + 2 = 0
x = -2
son's present age = 5 years
my present age = 5² + 5 = 30years