Question

My ques is the sum of all odd integers between 2 to 100 divisible by 3 ??

Answer 1

Answer:

1683

Step-by-step explanation:

AP: 3,6,9....99

a=3, d=3

An=99

An=a+(n-1)d

99=3+(n-1)3

99-3=(n-1)3

96=(n-1)3

96/3=n-1

32=n-1

32+1=n

33=n

n=33

Sn=n/2(a+An)

S(33)=33/2×(3+99)

=33/2×102

=33×51

=1683

HOPE THIS BRING A SMILE IN YOUR FACE