Question

my question is what is (n-1/n)^2

Answer 1

Hope this helps
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Answer 2

(n-1/n)²

It is in the form of (a-b)²

(a-b)² = a²+b²-2ab

→ (n-1/n)²

→ n²+(1/n)² - 2(n)(1/n)

→ n²+1/n² - 2

Hope it helps...