Question

my reminder theorem find the remainder when the P(x) is divided g(x), where p(x)= x cube- 6x square + 2x-4, g(x)= 1-3x by 2​

Answer 1

Answer:

Step-by-step explanation:

when we see any question suppose the dividend is x-a

they keep x-a=0

and substitute x=a

in equation

in the question

put g(x)=0

=1-3x/2=0

then comes out to be

x=1/3

p(x)=1/27-6/9+2/3-4