Question

N=2p-3 , p ∈ N and divide n² by 4 what will be the remainder?

Answer 1

Answer:

• Quotient = p^2 + 3p
• Remainder = 9

Step-by-step explanation:

n^2 = (2p - 3)^2

= 4p^2 - 2(2p)(-3) + 9

= 4p^2 + 12p + 9

Therefore,

n^2 ÷ 4

= (2p -3)^2 ÷ 4

= 4p^2 + 12p + 9 ÷ 4

= p^2 + 3p

• Quotient = p^2 + 3p
• Remainder = 9