n balls each of mass m impinge elastically in each second on a surface with velocity u. the average force experienced by the surface with be?
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Force = rate of change in momentum
Force = mdv/dt
Force = n*m(v2 - v1)/t
Force = n*m(u - (-u))/t
Final velocity is in opposite direction of initial velocity.
Force = 2nmu/t
According to question t = 1
Force = 2nmu
Force = mdv/dt
Force = n*m(v2 - v1)/t
Force = n*m(u - (-u))/t
Final velocity is in opposite direction of initial velocity.
Force = 2nmu/t
According to question t = 1
Force = 2nmu
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