Question

n(u)=200, n(A)=120, n(B)=50, n(AnB)=30 find n(A-B) and n(B-A)​

Answer 1

Answer:

The answers are 90 and 20 respectively

Step-by-step explanation:

• Formula: $n(A-B)=n(A)-n(A\cap B)$ and $n(B-A)=n(B)-n(A\cap B)$

           Here given $n(A)=120,n(B)=50,n(A\cap B)=30$

            Therefore $n(A-B)=120-30=90$

                     and  $n(B-A)=50-30=20$