Question

n1=3/8,n2=3/4,n1 is refractive index of denser medium then it critical angle is​

Answer 1

Answer:

Critical Angle = 30°

Explanation:

$n_{12} = \frac{n_{1} }{n_{2} } = \frac{\frac{3}{8} }{\frac{3}{4} } = \frac{3}{8} *\frac{4}{3} =\frac{1}{2}$

Critical angle = $sin^{-1}(\frac{1}{n} )$

⇒ $sin^{-1}(\frac{1}{2} )$

⇒ 30°

Answer 2

critical angle is 30°

explanation:

n1/n2=3/8×4/3=1/2