Question

निम्नलिखित आयनों में प्रत्येक के लिए 3d इलेक्ट्रॉनों की संख्या लिखिए-
[tex]Ti^{2+}, V^{2+},
Cr^{3+}, Mn^{2+}, Fe^{2+}, Fe^{3+}, Co^{2+}, Ni^{2+} Cu^{2+}[/tex]
आप इन जलयोजित आयनों (अष्टफलकीय) में पाँच 3d कक्षकों को किस प्रकार अधिग्रहीत करेंगे? दर्शाइए।

Answer 1

Answer:

are u new over there

Answer 2

Answer:

Explanation:

write using noble gas configuration

for all these elements the nearest noble gas is argon

ti can be written as ar 4s2 3d2

so ti+2 = ar 3d2

cr is written as ar  4s1 3d5

cr+3 can be written as ar 3d3

v can be written as ar 4s2 3d3

v+2 can be written as ar  3d3

mn is written as ar 4s2 3d5

mn+2 is written as  ar 3d5

fe can be written as ar 4s2 3d6

fe+2 is written as ar 3d6

fe+3 is written as 3d5

co can be written as ar 4s2 3d7

co+2 can be written as 3d7

ni can written as ar 4s2 3d8

ni+2 can be written as ar 3d8

cu can be written as ar 4s1 3d10

cu+2 can be written as 3d9