Question

निर्देशानुसार भाग दीजिए : (i) $5(2x + 1) (3x + 5) \div (2x + 1)$ (ii) $26xy(x + 5) (y - 4) \div 13x(y - 4)$ (iii) $52pqr (p + q) (q + r) (r + p) \div 10^4pq(q + r) (r + p)$ (iv) $20(y + 4) (y^2+ 5y + 3) \div 5(y + 4)$ (v) $x(x + 1) (x + 2) (x + 3) \div x(x + 1)$

Answer 1

Answer Explanation:

(i) 5(2x + 1)(3x + 5) ÷ (2x + 1)  

= [5(2x + 1)(3x + 5)] /(2x + 1)

= 5(3x + 5)      

 

(ii) 26xy(x + 5)(y - 4) ÷ 13x(y - 4)  

= [26xy(x + 5)(y - 4)] / [13x(y - 4)]

= 2y(x + 5)

 

(iii) 52pqr(p + q)(q + r)(r + p) ÷ 104pq(q + r)(r + p)

= [52pqr(p + q)(q + r)(r + p)] /[104pq(q + r)(r + p)]

= [52pqr(p + q)(q + r)(r + p)]/[52 * 2pq(q + r)(r + p)]

= r(r + p)/2

 

(iv) 20(y + 4)(y² + 5y + 3) ÷ 5(y + 4)  

= [20(y + 4)(y² + 5y + 3)]/[5(y + 4)]

= 4(y² + 5y + 3)

 

(v) x(x + 1)(x + 2)(x + 3) ÷ x(x + 1)  

= [x(x + 1)(x + 2)(x + 3)]/[x(x + 1)]

= (x + 2)(x + 3)

आशा है कि यह उत्तर आपकी अवश्य मदद करेगा।।।।  

इस पाठ से संबंधित कुछ और प्रश्न :

निम्नलिखित विभाजन कीजिए : (i) $(10x - 25) \div 5$ (ii) $(10x - 25) \div (2x - 5)$ (iii) $10y(6y + 21) \div 5(2y + 7)$ (iv) $9x^2y^2(3z - 24) \div 27xy(z - 8)$ (v) $96abc(3a - 12) (5b - 30) \div 144(a - 4) (b - 6)$

https://brainly.in/question/10768324

दिए हुए बहुपद को दिए हुए एकपदी से भाग दीजिए : (i) $(5x^2- 6x) \div 3x$ (ii) $(3y^8- 4y^6+ 5y^4) \div y^4$ (iii) $8(x^3y^2z^2+ x^2y^3z^2+ x^2y^2z^3) \div 4x^2y^2z^2$ (iv) $(x^3+ 2x^2+ 3x) \div 2x$ (v) $(p^3 q^6- p^6q^3) \div p^3q^3$

https://brainly.in/question/10768021

Answer 2

$\huge{\boxed{\red{\boxed{\mathfrak{\pink{Solution}}}}}}$

(i) 5(2x + 1)(3x + 5) ÷ (2x + 1)

= [5(2x + 1)(3x + 5)] /(2x + 1)

= 5(3x + 5)

(ii) 26xy(x + 5)(y - 4) ÷ 13x(y - 4)

= [26xy(x + 5)(y - 4)] / [13x(y - 4)]

= 2y(x + 5)

(iii) 52pqr(p + q)(q + r)(r + p) ÷ 104pq(q + r)(r + p)

= [52pqr(p + q)(q + r)(r + p)] /[104pq(q + r)(r + p)]

= [52pqr(p + q)(q + r)(r + p)]/[52 * 2pq(q + r)(r + p)]

= r(r + p)/2

(iv) 20(y + 4)(y² + 5y + 3) ÷ 5(y + 4)

= [20(y + 4)(y² + 5y + 3)]/[5(y + 4)]

= 4(y² + 5y + 3)

(v) x(x + 1)(x + 2)(x + 3) ÷ x(x + 1)

= [x(x + 1)(x + 2)(x + 3)]/[x(x + 1)]

= (x + 2)(x + 3)