Math, asked by zqueenzqueen85, 1 year ago

Nafisa is twice as old as sakina five years ago her age was three times sakina age find their present ages pls solve it fast

Answers

Answered by disha11100
2

HEY MATE!

HERE IS YOUR ANSWER:

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Answered by Anonymous
7

Solution :-

Let the age of Sakina = x ;

Age of Nasifa = 2x.

5 years ago :-

Age of Sakina = x - 5

Age of Nasifa = 2x - 5

According To Question :-

=) 2x - 5 = 3 (x - 5)

=) 2x - 5 = 3x - 15

=) - 5 + 15 = 3x - 2x

=) 10 = x

Age of Nasifa = 2 (10) = 20 years.

So, the Present Age of Sakina is 10 years ;

Present age of Nasifa is 20 years.

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