Chemistry, asked by carmaniac771, 10 months ago

NaHCO3 is heated such that the weight of residue formed is 0.265 g, the volume of CO2 formed at STP is




56 mL


112 mL


0.56 L


75 mL

Answers

Answered by angad201000
1

Answer:

75 ml is formed at stp the volume of co2

Answered by gch1OICO73
1

Answer:

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CHEMISTRY

2.0 g mixture of sodium carbonate and sodium bicarbonate on heating to constant mass gave 224 mL of CO

2

at NTP. The % mass of sodium bicarbonate in the mixture is:

December 27, 2019avatar

Dheerendra Chaudhari

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ANSWER

Sodium bicarbonate decomposes in

the following manner.

2NaHCO

3

→Na

2

CO

3

+H

2

O+CO

2

Sodium Carbonate is stable and

doesn't dissociate upon normal

heating.

Vol. of CO

2

=224ml

22.4Ltr=1mole

So moles of CO

2

=0.224/22.4=0.01mole

0.01mole=44×0.01g=0.44g

1 mole CO

2

is procured by 2 mole NaHCO

3

∴ Moles of NaHCO

3

=2×0.01=0.02

=0.02×84=1.689

% age =

Totalmass

mass

×100=

2

1.68

×100=84%

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