Math, asked by vasanth2006, 10 months ago

namans age isthree times his sons age. ten years ago, he was 5 times his sons age. find their present ages​

Answers

Answered by Panzer786
3

Hi,

Let the age of his son be x years.

Therefore,

Age of Naman = 3 × X = 3x years.

Before 10 years age of naman = 3x - 10 .

Before 10 Years age of his son = x - 10.

According to the question,

3x - 10 = 5 ( x - 10 )

3x - 10 = 5x - 50

3x - 5x = -50 + 10

-2x = -40

x = 40/2 = 20 years.

Age of son = x = 20 years.

And,

Age of Naman = 3x = 3* 20 = 60 years.

Hope it will help you;)

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