nC5=nC6 find n it's under combination. Please can someone help me solve it. I need answers fast
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Hi Samuel,
nc5 = nc6
n! / ((n-5)!*5!) = n! / ((n-6)!*6!
rearranging we get
(n-5)!*5! = (n-5)*(n-6)!*5!
(n-6)!*6! = (n-6)!*6*5!
equating above two, we get
(n-5)*(n-6)!*5! = (n-6)!*6*5!
solving above equation we get
(n-5)=6
n=11
Hope it helped.
Let me know if any further doubt.
Cheers !!!
nc5 = nc6
n! / ((n-5)!*5!) = n! / ((n-6)!*6!
rearranging we get
(n-5)!*5! = (n-5)*(n-6)!*5!
(n-6)!*6! = (n-6)!*6*5!
equating above two, we get
(n-5)*(n-6)!*5! = (n-6)!*6*5!
solving above equation we get
(n-5)=6
n=11
Hope it helped.
Let me know if any further doubt.
Cheers !!!
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