nilai k yang memenuhi agar persamaan kuadrat (1-k)x^2+4x-1=0 mempunyai dua akar yang sama ...
Answers
Answered by
0
d=0
b²-4ac=0
b=4 a=(1-k) c = -1
4²-4(1-k)(-1)=0
4 + 1-k=0
k=5 ans
b²-4ac=0
b=4 a=(1-k) c = -1
4²-4(1-k)(-1)=0
4 + 1-k=0
k=5 ans
Answered by
0
d=0
b²-4ac=0
b=4 a=(1-k) c = -1
4²-4(1-k)(-1)=0
4 + 1-k=0
k=5
b²-4ac=0
b=4 a=(1-k) c = -1
4²-4(1-k)(-1)=0
4 + 1-k=0
k=5
Similar questions