Question

Nilofer decides to distribute 200 chocolates equally to her students. But, 2 of her older students come and she has to redistribute the same chocolates to all of them now. Now, her present students get 5 chocolates lesser than what they were getting earlier. So, nilofer's present students are

Answer 1

Answer:

8

Step-by-step explanation:

Let the total number of students earlier = n

After 2 old students comes, total number of students = n + 2

Given that,

total number of chocolates = 200

So, earlier, chocolate for each students = 200 / n

When 2 students joins, chocolate foe each students = 200 / n + 2

According to Question,

(200 / n) - 5 = 200 / (n + 2)

(n + 2) (200 - 5 n) = 200 n

5 n^2 + 10 n - 400 = 0

5 n^2 + 50 n - 40 n - 400 = 0

5 n ( n + 10 ) - 40 ( n + 10 )  = 0

n = 8

Thus number of students earlier = 8

Answer 2

Answer:

Step-by-step explanation:

let total no. Of students earlier =n

Earlier each students could got

= 200/ n chocolates

Present,no. Of students= n + 2

now , each students can get

= 200 / (n + 2) chocolates

Accorting to question,

(200/n) - 5 = 200/(n+ 2)

200 [(1/n) - (1/n+2)] = 5

40×(n + 2 - n) = n ( n + 2)

n^2 + 2n - 80 = 0

n^2 + 10n - 8n + 80 = 0

n ( n + 10) - 8(n + 10) = 0

(n - 8) ( n + 10)

n = 8, - 10

neglect - 10, number of chocolates can't be -ve.

Thus, n = 8

Nilfofer's present students are

= n + 2 = 8 + 2 = 10

Answer: 10