Math, asked by nishan2788, 4 months ago

Nilu covers a distance by walking for 6 h,
while returning, his speed decreases by
2 km/h and he takes 9 h to cover the
same distance. What was her speed
while returning?
(a) 2 km/h
(b) 5 km/h
C) 4 km/h
(d) 7 km/h
(e) None of these​

Answers

Answered by EliteZeal
44

\huge{\blue{\bold{\underline{\underline{Answer :}}}}}

 \:\:

\large\underline{\green{\bf Given :-}}

 \:\:

  • Nilu covers a distance by walking for 6 h

 \:\:

  • While returning his speed decreases by 2 km/h

 \:\:

  • He took 9h to return covering the same distance

 \:\:

\large\underline{\red{\bf To \: Find :-}}

 \:\:

  • Speed while returning

 \:\:

\large\underline{\orange{\bf Solution :-}}

 \:\:

  • Let the distance be "d"

  • Let the original speed be "s"

 \:\:

We know that ,

 \:\:

➠ d = s × t ⚊⚊⚊⚊ ⓵

 \:\:

Where,

 \:\:

  • d = Distance

  • s = Speed

  • t = Time taken

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

Case 1 [ While Going ]

 \:\:

Nilu covers a distance by walking for 6 h

 \:\:

  • d = d

  • s = s

  • t = 6

 \:\:

Putting these values in ⓵

 \:\:

➜ d = s × t

 \:\:

➜ d = s × 6 ⚊⚊⚊⚊ ⓶

 \:\:

Case II [ While Returning ]

 \:\:

Also given that , While returning his speed decreases by 2 km/h and he took 9h to return covering the same distance

 \:\:

So,

 \:\:

  • d = d

  • s = s - 2

  • t = 9

 \:\:

Putting these values in ⓵

 \:\:

➜ d = s × t ⚊⚊⚊⚊ ⓷

 \:\:

➜ d = (s - 2) × 9 ⚊⚊⚊⚊ ⓷

 \:\:

Equation ⓶ = Equation ⓷

 \:\:

So,

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➜ s × 6 = (s - 2) × 9

 \:\:

➜ 6s = 9s - 18

 \:\:

➜ 9s - 6s = 18

 \:\:

➜ 3s = 18

 \:\:

 \sf s = \dfrac { 18 } { 3 }

 \:\:

➨ s = 6 km/hr ⚊⚊⚊⚊ ⓸

 \:\:

  • Hence the original speed is 6 km/hr

 \:\:

 \underline{\bold{\texttt{Speed while returning :}}}

 \:\:

Given that speed is decreased by 2

 \:\:

So,

 \:\:

➜ s - 2 ⚊⚊⚊⚊ ⓹

 \:\:

Putting s = 6 from ⓸ to ⓹

 \:\:

➜ 6 - 2

 \:\:

➨ 4 km/hr

 \:\:

  • Hence the speed while returning is 4 km/hr

 \:\:

Thus option (c) is correct

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