Nishu invested an amount of rs. 13,900 divided in two different schemes a and b at the simple interest rate of 14% p.A. And 11% p.A. Respectively. If the total amount of simple interest earned in 2 years be rs. 3508, what was the amount invested in scheme b?
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Answered by
7
According the conditions of a and b division = a+b = 13900;
Simple Interest formula = PRT/100;
(a*14*2/100) + (b*11*2/100) = 3508;
0.28a + 0.22b = 3508;
Now solving this two equations;
0.28a + 0.22b = 3508;
a+b = 13900;;
We get a = 7500 and b = 6400;
Answer- Rs. 6400 invested by b
Answered by
5
"We can take the sum spent in A scheme as Rs. X. The value of scheme B is Rs. 13900-x.
When we substitute the values in the following formula, we can get the following step.
Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100
= 28x - 22x = 350800 - (13900 x 22)
6x= 45000
X=45000/6
x= 7500.
So, sum spent in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
"
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