Question

Nitin walks at 3/4 of his usual speed and reaches his home 10 minutes late find the usual time taken by him to reach his destination.

Answer 1

Let his original speed be x m/s

original time t secs

New SPeed = 3x/4 m/s

New Time = t  + 10 secs , because he reached 10 mins late

Distance will be same in both cases

We know that Distance = speed * time

Distance with original speed  = Distance with new speed

Original speed * Original time  = New speed * New time

x * t = 3x/4 * (t + 10)

After solving , we get :

t = 30 secs

Happy Learning :)

Answer 2

Answer:

Step-by-step explanation:

30 seconds

Hope you can understand the concept

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