Nitrogen gas is filled in a contaner of volume 2.32L at 300K and 4.7 atmospheric pressure calculate the number of moles of gas? (R=0.0821)
Answers
Answer:
You also need the volume.
Then, you insert the pressure, volume, and temperature into the expression and calculate the number of moles.
The Ideal Gas Law is
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
a
a
p
V
=
n
R
T
a
a
∣
∣
−−−−−−−−−−−−−−−
We can rearrange this formula to get the number of moles,
n
.
n
=
p
V
R
T
EXAMPLE
A 3.00 L container is filled with neon gas at 770 mmHg and 27 °C. How many moles of neon are present?
Solution
Step 1. List the information given, making conversions as necessary.
p
=
770
mmHg
×
1 atm
760
mmHg
=
1.013 atm
V
=
3.00 L
R
=
0.082 06 L⋅atm⋅K
-1
mol
-1
T
=
(30 + 273.15) K = 303.15 K
Step 2. Calculate the number of moles.
n
=
1.013
atm
×
3.00
L
0.082 06
L⋅atm⋅K
-1
mol
-1
×
300.15
K
=
0.123 mol
There are 0.123 mol of neon in the container.
Explanation:
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Answer: n=0.4357
Explanation: V=2.32L
T=32 C=305k
P=4.7ATM
According to Equation
PV=nRT
4.7 × 2.32 = n × 0.08206 × 305
n = (4.7 × 2.32) / (0.08206 × 305)
n=0.4357Mol
Hence, number of moles of N2 gas produced is 0.4357 mol.