No. of bacteria increased to 650000 within 2 hours when it was increasing at a rate of 5 % per hour. what was the number /count of bacteria before 2 hours?
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Step-by-step explanation:
We have, P
0
= Original count of bacteria=650000
Rate of increase =R=2.5% per hour,
Time =2 hours
∴ Bacteria count after 2 hours = P
P=P
0
(1+
100
R
)
T
=650000×(1+ 1002.5 ) 2
=650000× 100102.5 × 100102.5
=6.5133318300000.15
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