Chemistry, asked by hari234, 1 year ago

no of moles of electron present in 1kg of electron is

Answers

Answered by Shruti03
2
Mass of 1 electron = 9.1 * 10^-31 kg

Therefore,no: of electron in 1kg = 1.09 * 10^32 electron

1 mole of electrons= 6.023 * 10^23 electrons

No of moles=no of electrons/ no of electrons in one mole= (1.09 * 10^30)/(6.023 * 10^23)=1.8 * 10^8 electrons


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Answered by Haripriyahp
2
Mass of 1 electron = 9.1 * 10^-31 kg

Therefore,no: of electron in 1kg = 1.09 * 10^32 electron

1 mole of electrons= 6.023 * 10^23 electrons

No of moles=no of electrons/ no of electrons in one mole= (1.09 * 10^30)/(6.023 * 10^23)=1.8 * 10^8 electrons

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