Question

no of moles present in 0.144g of oxygen




also,what is 1+1+1-2+3*4+3-100

Answer 1

Step-by-step explanation :

No. of moles = W in g / W in g/mol

Here W in gram for Oxygen = 0.144 g

Atomic mass of O = 16 g

Molecular mass of O2 = 16 g × 2 = 32 gram

Hence, no. of moles = 0.144/32

= 0.072/16 = 0.0045 moles

Hence 0.0045 moles are present in 0.144 g of Oxygen.

Now, 1 + 1 + 1 - 2 +3 × 4 + 3 - 100

According to BODMAS,

= 1 + 1 + 1 - 2 + 12 + 3 - 100

= 18 - 102 = - 84