Question

no. of prime factors in 6^333×7^222×8^111

Answer 1

HEya friend!!



$6^{333 } * 7^{222 } * 8^{111}$

= $(2X3)^{333} * 7^{222 } * (2^{3})^{111}$

[tex] = 2^{333} * 3^{333 }* 7^{222} *2^{333}[/tex]

We rewrite 6,7,8 as exponents of prime numbers

HENCE 

Total no of prime factors will be

= 333 + 333 + 222 + 333

= 1221

HOPE IT HELPS!!!!!!!!!!