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Answer 1

Answer:

x = 55°

Step-by-step explanation:

Given :

≤BCE = 25 °

≤CEF = 150°

AB is parallel to CD

≤ECD = 180° - ≤FEC (Co-Interior Angles)

          = 180° - 150°

           = 30°

≤x = ≤BCD (Aternative interior angles)

≤x = ≤BCE + ≤ECD  

≤x = 25° + 30°

≤x = 55°

Hope it helps you

Answer 2

Solution :-

since EF || CD ,

→ ∠FEC + ∠ECD = 180° { Consecutive Interior Angles equal to 180°. }

so,

→ 150° + ∠ECD = 180°

→ ∠ECD = 180° - 150°

→ ∠ECD = 30°

now,

→ ∠BCD = ∠ECD + ∠BCE

→ ∠BCD = 30° + 25°

→ ∠BCD = 55°

now, we have given that, AB || CD .

therefore,

→ ∠ABC = ∠BCD { Alternate interior angles. }

→ x° = 55° (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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