Question

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Answer 1

Heya...

heat taken = heat given

let mass be m

$m \times 540 + m(100 - 80) =$

$(1.1 + 0.02)(80 - 15)$

m = 0.13

hope it helps

Answer 2

Steam at 100oC is passed into 1.1kg of water contained in a calorimeter of water equivalent 0.02kg at 15oC till the temperature of the calorimeter rises to 800C . The mass of steam condensed in kilogram is :(a)0.13 (b)0.065 (c)0.260 (d)0.135 0 Follow 0student-name Ruhhi Ralhan answered thisin Physics, ClassDear Student,Given:Mass of water and calorimeter=(1.10+0.02)=1.12 kgspecific heat capacity of water=4.184×103 Jkg-1K-1Now, using Q=mcΔTheat gained by calorimeter and water,Let the mass of steam=m kgLatent heat of vaporization of water at 100°C=540 Cal/g=540×4.184×103 Jkg-1Heat lost by steam,now equate above two equations