Question

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Answer 1

Answer:

$(x + a)(x + b) \\ = {x}^{2} + (a + b)x + ab \\ means \\ (a + b) = 5 \\ ab = 6 \\ \\ \\ square \: (a + b) = 5 \\ {(a + b)}^{2} = 25 \\ {a}^{2} + {b}^{2} + 2ab = 25 \\ < ab = 6 > \\ {a}^{2} + {b}^{2} = 25 - 12 = 13 \\ {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ = 13 - 12 = 1 \\ (a - b) = 1$

Answer 2

Answer:

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