Question

Normal water contains isotope of hydrogen tritium. It has a half life of 12.3 year .
Determine the age of a bottle of wine whose H radiation is about 1/10 that present in
new wine.

Answer 1

it is 13.544 approximately

Answer 2

Answer:The age of a bottle of wine is 40.90 years.

Explanation:

Half-life of sample of hydrogen tritium $t_{\frac{1}{2}}$= 12.3 years

Initial radiation of H radiation present in  new wine = $N_o$

Present radiation of wine whose H radiation is about 1/10 that present in new wine.N = $\frac{1}{10}N_o$

Let the age of wine be t

$\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{12.3 years}=0.0563 year^{-1}$

$N=N_o\times e^{-\lambda t}$

$ln[\frac{1}{10}N_o]=ln[N_o]-0.0563 year^{-1}\times t$

$2.303\times \log[0.1]=-0.0563 year^{-1}\times t$

t = 40.90 years

The age of a bottle of wine is 40.90 years.