Now the age of mother and daughter together is 78. The difference in their ages after 5 years is 36.What were their ages 3 years ago?
Answers
let the present age of mother be = x years
and her daughter's age be = y years
According to question,
x + y = 78 -------------------1
after 5 years,
(x + 5) - (y + 5) = 36
x + 5 - y - 5 = 36
x - y = 36 -------------------2
equation ¹ - equation ²
(x + y) - (x - y) = 78 - 36
x + y - x + y = 42
2y = 42
y = 21
now substituting value of y in equation 1
x + y = 78
x + 21 = 78
x = 78 - 21
x = 57
hence, the present ages of mother and her daughter is 57 and 21 years respectively
mother's age three years ago
= 57 - 3 = 54
daughter's age three years ago
= 21 - 3 = 18
Total age of mother and daughter = 78 years
Difference of their ages after 5 years = 36
The age of mother 3 years ago.
The age of daughter 3 years ago.
Given, total age of mother and daughter is 78 years.
Difference of their ages after 5 years = 36
Let us consider the ages of mother and daughter to be x and y respectively
Equation (1),
After 5 years ages would be,
According to the question,
Substituting the value of x from first equation,
Finding the value of y,
Ages 3 years ago = x -3 and y - 3
x = 54
y = 18
Therefore, the age of mother is 54 and the daughter is 18 years.