nth term of AP is a5 if a1+a2+a3=102 a1=15then find a10
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Answer: 186
Step-by-step explanation:
a1 + a2 + a3 = 102
therefore
a+a+d+a+2d=102
3a+3d=102
that is a+d=34
we know a =15
hence d=19
therefore a10 is a+9d
15+9*+=186
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