Question

nucleus and yellow light of wavelength 150 and passes through two slits separated by 0.1 M the interference pattern is observed on screen 0.5 mm behind the streets find the distance between bright fringes of order 1 and 3 ​

Answer 1

Given that,

Wavelength = 150 nm

Separated slit = 0.1 m

Distance = 0.5mm

We need to calculate the distance for order 1

Using formula of distance

$y=\dfrac{m\lambda D}{d}$

Where, $\lambda$ = wavelength

D = Distance between slit and screen

d = slit distance

Put the value into the formula

$y_{1}=\dfrac{1\times150\times10^{-9}\times0.1}{0.5\times10^{-3}}$

$y_{1}=0.00003\ m$

$y_{1}=0.03\ mm$

We need to calculate the distance for order 3

Using formula of distance

$y=\dfrac{m\lambda D}{d}$

Put the value into the formula

$y_{3}=\dfrac{3\times150\times10^{-9}\times0.1}{0.5\times10^{-3}}$

$y_{3}=0.00009\ m$

$y_{3}=0.09\ mm$

We need to calculate the distance between bright fringes

Using formula of distance

$\Delta y=y_{3}-y_{1}$

Put the value into the formula

$\Delta y=0.09-0.03$

$\Delta y=0.06\ mm$

Hence, The distance between bright fringes of order 1 and 3  is 0.06 mm.