Question

number of 0 in 3⁵×2³×5⁷×7²are : ​

Answer 1

Answer:

$\sf 3$

Step-by-step explanation:

The number of zeroes can be calculated by knowing how many times "10" are there in the product.

${3}^{5} \times {2}^{3} \times {5}^{7} \times {7}^{2}$

$\implies{3}^{5} \times {2}^{3} \times {5}^{3} \times {5}^{4} \times {7}^{2}$

$\implies{3}^{5} \times {5}^{4} \times {7}^{2} \times {(2 \times 5)}^{3}$

$\implies{3}^{5} \times {5}^{4} \times {7}^{2} \times {(10)}^{3}$

$\sf \purple{here : }$

we have 10³ which can be represented as 10×10×10.

Since there are 3 times "10" .Therefore 3 zeroes.