number of atoms in 52 a.m.u of helium
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Answered by
2
Explanation:
no.of mole=52/4=13
so,no.of atoms=13×6.022×10^23
Answered by
4
Atomic mass of He = 4u
Given mass = 52u
No. of moles = Given mass/Atomic mass
= 52/4
=13 moles
No of atoms = Avogadro No * No of moles
6.022*10^23 * 13
= 78.286 * 10²³ atoms are present in 52 amu of He
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