Chemistry, asked by hasu30, 11 months ago

number of atoms in 52 a.m.u of helium ​

Answers

Answered by ghanshyamkumar51
2

Explanation:

no.of mole=52/4=13

so,no.of atoms=13×6.022×10^23

Answered by malavikabala012003
4

Atomic mass of He = 4u

Given mass = 52u

No. of moles = Given mass/Atomic mass

                     = 52/4

                     =13 moles

No of atoms = Avogadro No * No of moles

                      6.022*10^23 * 13

                     = 78.286 * 10²³ atoms are present in 52 amu of He

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